Walkthrough
Example 01 — One number is locked to a box
The rectangle numbers are 3 and 4. The two exceptional corners r8c6 and r9c6 share column 6, number 4 appears nowhere else in column 6. Therefore 4 must occupy one of those two corners.
If cell r8c6 were number 3, then number 4 would be pushed into cell r9c6, in turn, cell r8c1 would be 4, and cell r9c1 would be 3, now it would end up with a deadly pattern of four corners' values liking this:
you could swap left and right cornor pairs, or above and below cornor pairs, while the rest of the soduku grid would still be perfeectly valid.
Similarly, if cell r9c6 were number 3, it would end up with the same deadly pattern. Therefore, both cells r8c6 and r9c6 cannot be number 3.
What to notice: The house restriction proves one rectangle number must be present; uniqueness then eliminates the other number.